5x^4-3/x^2=0

Solution for 5x^4-3/x^2=0 equation:

D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5*x^4-(3/(x^2)) = 0

5*x^4-3*x^-2 = 0

t_1 = x^2

5*t_1^2-3*t_1^-1 = 0

t_1^-1*(5*t_1^3-3) = 0

5*t_1^3 = 3 // : 5

t_1^3 = 3/5

t_1^3 = 3/5 // ^ 1/3

t_1 = (3/5)^(1/3)

1/t_1 = 0

1*t_1^-1 = 0 // : 1

t_1^-1 = 0

t_1 należy do O

t_1 = (3/5)^(1/3)

x^2-(3/5)^(1/3) = 0

1*x^2 = (3/5)^(1/3) // : 1

x^2 = (3/5)^(1/3)

x^2 = (3/5)^(1/3) // ^ 1/2

abs(x) = (3/5)^(1/6)

x = (3/5)^(1/6) or x = -(3/5)^(1/6)

x in { (3/5)^(1/6), -(3/5)^(1/6) }